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The volume of oxygen liberated from 15 m...

The volume of oxygen liberated from `15 ml` of 20 volume `H_(2)O_(2)` is

A

250 ml

B

300 ml

C

150 ml

D

200 ml

Text Solution

Verified by Experts

The correct Answer is:
B
Quantity of `H_(2)O_(2)` =15 ml and volume of `H_(2)O_(2)=20`
We know that 20 volume of `H_(2)O_(2)` means 1 liter of this solution will give 20 l of oxygen at N.T.P.
Since , oxygen liberated from 1000ml (1 l) of `H_(2)O_(2)=20 ` l , therefore oxygen liberated from 15 ml of `H_(2)O_(2) =20/1000xx15=0.3` l =300 ml
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