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In transforming 0.01 mole of PbS to PbSO...

In transforming `0.01` mole of `PbS` to `PbSO_(4)`, the volume of '10 volume `H_(2)O_(2)` required will be `:`

A

11.2 ml

B

22.4 ml

C

33.6 ml

D

44.8 ml

Text Solution

Verified by Experts

The correct Answer is:
D
`PbS+4H_(2)O_(2) to underset("white")(PbSO_(4))+4H_(2)O`
`{:(4H_(2)O_(2) ,to, 4H_(2)O ,+,2O_(2)),(4(2+32),,,,2xx22.4"liter"),(=136g,,,,"at NTP"):}`
From the above equation we can derive that in transforming 1 mole of PbS to `PbSO_(4)` the volume of '10 volume' of `H_(2)O_(2)` of required is 44.8 ml time at NTP.
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