`Na_2O_(2)` is producedc in reaction between `H_(2)O_(2)` and NaOH. Here the role of `H_(2)O_(2)` is

Options

A. As an oxidising agent
B. As an acid
C. As a base
D. As a reducing agent

Explanation

To understand the role of hydrogen peroxide (H₂O₂) in the reaction with sodium hydroxide (NaOH) to produce sodium peroxide (Na₂O₂), we can break down the process step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are sodium hydroxide (NaOH) and hydrogen peroxide (H₂O₂).

2. **Write the Reaction**: The reaction can be represented as:
\[ 2 \text{NaOH} + \text{H}_2\text{O}_2 \rightarrow \text{Na}_2\text{O}_2 + 2 \text{H}_2\text{O} \]

3. **Understanding the Products**: The products of this reaction are sodium peroxide (Na₂O₂) and water (H₂O). Sodium peroxide is an important compound that can be formed through this reaction.

4. **Role of H₂O₂**: In this reaction, hydrogen peroxide acts as an oxidizing agent. It donates oxygen to the sodium hydroxide, facilitating the formation of sodium peroxide.

5. **Oxidizing Agent Function**: As an oxidizing agent, H₂O₂ causes the oxidation of sodium hydroxide, leading to the formation of Na₂O₂. The oxygen from H₂O₂ is incorporated into the product.

6. **Conclusion**: Therefore, the role of H₂O₂ in this reaction is primarily as an oxidizing agent that helps in the formation of sodium peroxide from sodium hydroxide.

### Final Answer:
The role of H₂O₂ in the reaction with NaOH is that of an oxidizing agent, facilitating the formation of sodium peroxide (Na₂O₂).

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