Which of the following statements is incorrect

Options

A. Aluminium reacts with excess NaOH to give `Al(OH)_(3)`
B. `NaHCO_(3)` on heating gives `Na_(2)CO_(3)`
C. Pure sodium metal dissolves in liquid ammonia to give blue solution
D. NaOH reacts with glass to give sodium silicate

Explanation

To determine which statement is incorrect, let's analyze each statement one by one:

### Step 1: Analyze the First Statement
**Statement:** Aluminium reacts with excess NaOH to give Al(OH)₃.

- When aluminium (Al) reacts with excess sodium hydroxide (NaOH), it does not produce aluminium hydroxide (Al(OH)₃) directly. Instead, it forms sodium tetrahydroxoaluminate(III) [Na₃Al(OH)₆] in the presence of excess NaOH.
- Therefore, this statement is **incorrect**.

### Step 2: Analyze the Second Statement
**Statement:** When we heat NaHCO₃, we get Na₂CO₃.

- Heating sodium bicarbonate (NaHCO₃) decomposes it into sodium carbonate (Na₂CO₃), water (H₂O), and carbon dioxide (CO₂).
- The reaction is:
\[ 2 \text{NaHCO}_3 \rightarrow \text{Na}_2\text{CO}_3 + \text{H}_2\text{O} + \text{CO}_2 \]
- This statement is **correct**.

### Step 3: Analyze the Third Statement
**Statement:** Pure sodium metal dissolves in liquid ammonia and gives a blue solution.

- When sodium metal is dissolved in liquid ammonia, it forms a deep blue solution due to the formation of solvated electrons.
- This statement is **correct**.

### Step 4: Analyze the Fourth Statement
**Statement:** NaOH reacts with glass to give sodium silicate.

- Sodium hydroxide (NaOH) can react with silica (SiO₂) present in glass to form sodium silicate (Na₂SiO₃).
- This statement is **correct**.

### Conclusion
After analyzing all statements, we find that the first statement is incorrect. Therefore, the answer to the question is:

**Answer:** The incorrect statement is the first one: "Aluminium reacts with excess NaOH to give Al(OH)₃."

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