Diborane combines with ammonia at `120^(@)C` to give

Options

A. `B_(2)H_(6).NH_(3)`
B. `B_(2)H_(6).2NH_(3)`
C. `B_(2)H_(6).3NH_(3)`
D. `B_(2)H_(6).4NH_(3)`

Answer

To solve the question of what diborane combines with ammonia at 120°C to produce, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are diborane (B2H6) and ammonia (NH3).

2. **Understand the Reaction Conditions**:
- The reaction occurs at a temperature of 120°C. This elevated temperature can influence the reaction pathway and the products formed.

3. **Write the Reaction**:
- When diborane reacts with ammonia, the initial product formed is a complex. The reaction can be represented as:
\[ B_2H_6 + 2NH_3 \rightarrow B_2H_6 \cdot 2NH_3 \]
- The product formed is known as borazine, which can be represented as B2H6·2NH3.

4. **Further Breakdown of the Product**:
- Borazine (B2H6·2NH3) can further decompose under certain conditions to yield:
\[ B_3N_3H_6 + 12H_2 \]
- Here, B3N3H6 is known as inorganic benzene.

5. **Final Product Identification**:
- The primary product of the reaction at 120°C is borazine (B2H6·2NH3).

### Final Answer:
The product of the reaction between diborane and ammonia at 120°C is borazine, represented as \( B_2H_6 \cdot 2NH_3 \).

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