Aluminium chloride exists as a dimer, `Al_(2)Cl_(6)` in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives :

Options

A. `[Al(OH)_(6)]^(3-)+3HCl`
B. `[Al(H_(2)O)_(6)]^(3+) +3Cl^(-)`
C. `Al^(3+)+3Cl^(-)`
D. `Al_(2)O_(3)+6HCl`

Answer

B

Explanation

`Al_(2)Cl_6 +12 H_(2)O hArr 2[Al(H_(2)O)_(6)]^(3+) +6Cl^(-)`