`SiCl_(4)` on hydrolysis forms 'X' and HCl, compound 'X' losses water at `1000^(@)C` and gives 'Y'. Compounds 'X' and 'Y' are respectively

Options

A. `H_(2)SiCl_(6),SiO_(2)`
B. `H_(4)SiO_(4),Si`
C. `SiO_(2),Si`
D. `H_(4)SiO_(4),SiO_(2)`

Answer

To solve the problem step by step, we will analyze the hydrolysis of SiCl₄ and the subsequent reactions.

### Step 1: Hydrolysis of SiCl₄
When silicon tetrachloride (SiCl₄) undergoes hydrolysis, it reacts with water (H₂O) to form silicic acid (Si(OH)₄) and hydrochloric acid (HCl).

**Reaction:**
\[ \text{SiCl}_4 + 4 \text{H}_2\text{O} \rightarrow \text{Si(OH)}_4 + 4 \text{HCl} \]

### Step 2: Identify Compound 'X'
From the reaction above, we can identify compound 'X' as silicic acid, which is represented by the formula Si(OH)₄.

### Step 3: Heating Compound 'X'
Next, we need to consider what happens when silicic acid (Si(OH)₄) is heated to 1000°C. Upon heating, Si(OH)₄ loses water (H₂O) and forms silicon dioxide (SiO₂).

**Reaction:**
\[ \text{Si(OH)}_4 \xrightarrow{1000^\circ C} \text{SiO}_2 + 2 \text{H}_2\text{O} \]

### Step 4: Identify Compound 'Y'
From the reaction above, we can identify compound 'Y' as silicon dioxide (SiO₂).

### Final Answer
Thus, the compounds 'X' and 'Y' are:
- **X:** Si(OH)₄ (Silicic acid)
- **Y:** SiO₂ (Silicon dioxide)