Which of the following compounds is sparingly soluble in ammonia

Options

A. AgI
B. AgBr
C. AgCl
D. `CuCl_(2)`

Explanation

To determine which of the given compounds is sparingly soluble in ammonia, we can analyze the solubility of each compound based on their ionic characteristics.

### Step-by-Step Solution:

1. **Identify the Compounds**: The compounds given are AgI, AgBr, AgCl, and CuCl2.

2. **Understand Solubility in Ammonia**: Ammonia (NH₃) can dissolve certain ionic compounds to varying degrees. The solubility often depends on the nature of the ions involved. Compounds with more covalent character tend to be less soluble in ammonia.

3. **Analyze Each Compound**:
- **AgI (Silver Iodide)**: AgI is known to have a significant covalent character due to the large size of the iodide ion compared to silver. This makes AgI sparingly soluble in ammonia.
- **AgBr (Silver Bromide)**: AgBr is more soluble than AgI but still has some covalent character, making it less soluble than AgCl.
- **AgCl (Silver Chloride)**: AgCl is more soluble in ammonia compared to AgI and AgBr.
- **CuCl2 (Copper(II) Chloride)**: CuCl2 is generally soluble in ammonia due to the presence of the Cu²⁺ ion, which forms complex ions with ammonia.

4. **Conclusion**: Among the compounds listed, AgI is the one that is sparingly soluble in ammonia due to its strong covalent character and lower ionic character.

### Final Answer:
**AgI (Silver Iodide)** is sparingly soluble in ammonia.