Which of the following is most basic

Options

A. `NF_(3)`
B. `NCl_(3)`
C. `NBr_(3)`
D. `NI_(3)`

Answer

To determine which of the given compounds (NF3, NCl3, NBr3, and NI3) is the most basic, we need to analyze the basicity of each compound based on the electronegativity of the halogen atoms bonded to nitrogen.

### Step-by-Step Solution:

1. **Understanding Basicity**:
Basicity refers to the ability of a compound to donate a lone pair of electrons. In the context of nitrogen halides, the basicity is influenced by the electronegativity of the halogen atom.

2. **Electronegativity of Halogens**:
The electronegativity of the halogens in the compounds is as follows:
- Fluorine (F) > Chlorine (Cl) > Bromine (Br) > Iodine (I)
This means that fluorine is the most electronegative, while iodine is the least electronegative.

3. **Analyzing NF3**:
- In NF3, fluorine is highly electronegative, which pulls the electron density away from nitrogen. This makes it difficult for nitrogen to donate its lone pair, resulting in low basicity.

4. **Analyzing NCl3**:
- In NCl3, chlorine is less electronegative than fluorine but still relatively electronegative. Thus, it also has low basicity, but it is higher than NF3.

5. **Analyzing NBr3**:
- NBr3 has bromine, which is less electronegative than chlorine. Therefore, NBr3 is more basic than both NF3 and NCl3.

6. **Analyzing NI3**:
- In NI3, iodine is the least electronegative of all the halogens considered. This means that it does not pull electron density away from nitrogen as strongly as the other halogens do, allowing nitrogen to more readily donate its lone pair. Thus, NI3 is the most basic among the compounds listed.

7. **Conclusion**:
Based on the analysis, the order of basicity from least to most basic is:
- NF3 < NCl3 < NBr3 < NI3
Therefore, the most basic compound is **NI3**.

### Final Answer:
The most basic compound among NF3, NCl3, NBr3, and NI3 is **NI3**.