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The oxidation number of xenon in XeOF(2)...

The oxidation number of xenon in `XeOF_(2)` is

A

Zero

B

2

C

4

D

3

Text Solution

Verified by Experts

The correct Answer is:
C

Suppose the oxidation state of Xe is x. `XeOF_(2)`
x + (-2) + 2(-1) =0 `rArr ` x-2-2=0 `rArr` x=4.
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