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H(2)SO(4) cannot be used to prepare HBr ...

`H_(2)SO_(4)` cannot be used to prepare HBr from NaBr as it

A

Reacts slowly with NaBr

B

Oxidises HBr

C

Reduces HBr

D

Disproportionate HBr

Text Solution

Verified by Experts

The correct Answer is:
B
HBr is not prepared by heating NaBr with conc. `H_(2)SO_(4)` because HBr is a strong reducing agent and reduce `H_(2)SO_(4)` to `SO_(2)` and get itself oxidised to bromine.
`NaBr + H_(2)SO_(4) to NaHSO_(4) +HBr`
`H_(2)SO_(4) +2HBr to SO_(2) +Br_(2) +2H_(2)O`
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