Sodium oxalate on heating with conc. `H_(2)SO_(4)` gives

Options

A. CO only
B. `CO_(2)` only
C. CO and `CO_(2)`
D. `SO_(2)` and `SO_(3)`

Explanation

To solve the problem of what sodium oxalate produces when heated with concentrated sulfuric acid, we can follow these steps:

### Step 1: Write the Reactants
We start with sodium oxalate (Na2C2O4) and concentrated sulfuric acid (H2SO4).

### Step 2: Identify the Reaction
When sodium oxalate is heated with concentrated sulfuric acid, it decomposes. The sulfuric acid acts as a dehydrating agent, leading to the formation of oxalic acid (H2C2O4) initially.

### Step 3: Write the Initial Reaction
The initial reaction can be written as:
\[ \text{Na}_2\text{C}_2\text{O}_4 + \text{H}_2\text{SO}_4 \rightarrow \text{H}_2\text{C}_2\text{O}_4 + \text{Na}_2\text{SO}_4 \]

### Step 4: Decomposition of Oxalic Acid
Upon further heating, oxalic acid decomposes into carbon monoxide (CO), carbon dioxide (CO2), and water (H2O):
\[ \text{H}_2\text{C}_2\text{O}_4 \rightarrow \text{CO} + \text{CO}_2 + \text{H}_2\text{O} \]

### Step 5: Combine the Products
Combining the products from both reactions, we get:
- Sodium sulfate (Na2SO4)
- Carbon monoxide (CO)
- Carbon dioxide (CO2)
- Water (H2O)

### Final Products
Thus, the final products of the reaction when sodium oxalate is heated with concentrated sulfuric acid are:
\[ \text{Na}_2\text{SO}_4, \text{CO}, \text{CO}_2, \text{H}_2\text{O} \]

### Summary of the Reaction
The complete reaction can be summarized as:
\[ \text{Na}_2\text{C}_2\text{O}_4 + \text{H}_2\text{SO}_4 \xrightarrow{\text{heat}} \text{Na}_2\text{SO}_4 + \text{CO} + \text{CO}_2 + \text{H}_2\text{O} \]