The pair(s) of reagents that yield paramagnetic species is/are

Options

A. Na and excess of `NH_(3)`
B. K and excess of `O_(2)`
C. cu and dilute `HNO_(3)`
D. `O_(2)` and 2-ethylanthraquinol

Answer

A, B, C

Explanation

`Na+ NH_(3)"(excess") to ` dilute solution of sodium in liquid `NH_(3)` (which is paramagnetic)
` K + O_(2) ("excess") to KO_(2)` (`O_(2)^(-)` is paramagnetic )
`Cu + "dilute" HNO_(3) to Cu(NO_(3))_(2) + NO` (NO is paramagnetic)
`O_(2) +2 ` -ethylanthraquinol `to ` 2-ethylantraquinone `+H_(2)O_(2)` (Diamagnetic)