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Three moles of B(2)H(6) are completely r...

Three moles of `B_(2)H_(6)` are completely reacted with methanol. The number of moles of boron containing product formed is:

Text Solution

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The correct Answer is:
6
`B_(2)H_(6) +6CH_(3)OH to 2B(OCH_(3))_(3) + 6H_(2)`
For 3 moles of `B_(2)H_(6)` mole of B containing product formed =6
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