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What mass (in mg) of available O(2) per ...

What mass (in mg) of available `O_(2)` per liter is present in the a solution of `H_(2)O_(2)` 10 mL of which when treated requires 25 mL of N/20 `KMnO_(4)` for complete oxidation of it

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Verified by Experts

The correct Answer is:
2
The given reaction is
`2KMnO_(4) + 5H_(2)O_(2) + 4H_(2)SO_(4) to 2KHSO_(4) + 2MnSO_(4) + 8H_(2)O + 5O_(2)`
meq. Of `O_(2)` =meg . Of `H_(2)O_(2) =` meq. Of `KMnO_(4)`
`Nxx10=25xx1/20`
`:. N_(H_(2)O_(2)) =25/200 =0.125 rArr N_(O_(2))=0.125`
or `W_(O_(2))=0.125xx16 =2g//L`
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