Match list I with list II and select the correct answer using the codes given below the lists.

Options

A. A-1, B-3, C-5, D-4
B. A-2, B-3, C-5, D-1
C. A-4, B-3, C-5, D-1
D. A-4, B-5, C-3, D-1

Answer

C

Explanation

Magnetic moment, `mu=sqrt(n(n+2))`
Where n = number of unpaired electrons
`"For "Cr^(3+)(3s^(2)3p^(6)3d^(3)),mu=sqrt(3(3+2))=sqrt(15)B.M.`
`"For "Fe^(2+)(3s^(2)3p^(6)3d^(3)),mu=sqrt(4(4+2))=sqrt(24)B.M.`
`"For "Ni^(2+)(3s^(2)3p^(6)3d^(3)),mu=sqrt(2(2+2))=sqrt(8)B.M.`
`"For "Mn^(2+)(3s^(2)3p^(6)3d^(3)),mu=sqrt(5(5+2))=sqrt(35)B.M.`