A copper coin is completely covered with a gold film and is placed in dilute `HNO_(3)`. This will result in formation of

Options

A. Gold nitrate
B. Copper nitrate
C. Nond of these
D. Purple of cassius

Explanation

To solve the problem, we need to analyze the situation where a copper coin is covered with a gold film and then placed in dilute HNO₃ (nitric acid).

### Step-by-Step Solution:

1. **Identify the Metals Involved**:
- The coin is made of copper (Cu).
- The coin is covered with a gold (Au) film.

2. **Understand the Reactivity of Gold**:
- Gold is a noble metal, which means it is resistant to corrosion and does not react with most acids, including dilute nitric acid.

3. **Consider the Reaction of Copper with Dilute HNO₃**:
- Copper can react with dilute nitric acid. The reaction of copper with dilute HNO₃ produces copper(II) nitrate (Cu(NO₃)₂) and nitrogen oxides (NO or NO₂) as by-products.
- The reaction can be represented as:
\[ \text{Cu} + 2 \text{HNO}_3 \rightarrow \text{Cu(NO}_3)_2 + \text{NO} + \text{H}_2\text{O} \]

4. **Determine the Effect of the Gold Coating**:
- Since the copper coin is completely covered with a gold film, the gold will prevent any direct contact of the copper with the nitric acid.
- Therefore, the copper beneath the gold film will not react with the dilute HNO₃, and no copper nitrate will be formed.

5. **Conclusion**:
- Since the gold does not react with the acid, and the copper is protected by the gold film, there will be no formation of gold nitrate or copper nitrate.
- The final answer is that there will be no reaction, and thus no products will be formed.

### Final Answer:
The result of placing a copper coin covered with a gold film in dilute HNO₃ is that **no reaction occurs**, and therefore, **none of the products listed (gold nitrate, copper nitrate, etc.) will be formed**.

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