The compound `ZnFe_(2)O_(4)` is

Options

A. A normal spinel compound
B. Interstitial compound
C. Covalent compound
D. Co-ordination compound

Explanation

To determine the nature of the compound `ZnFe₂O₄`, we need to analyze its structure and classification.

### Step-by-Step Solution:

1. **Identify the Compound**:
The compound in question is `ZnFe₂O₄`. This compound consists of zinc (Zn) and iron (Fe) in combination with oxygen (O).

2. **Recognize the Structure**:
The formula `ZnFe₂O₄` indicates that it contains one zinc ion and two iron ions per formula unit, along with four oxide ions. This suggests a specific arrangement of these ions.

3. **Classification of Spinels**:
Compounds of the form `AB₂O₄` (where A and B are metal ions) are typically classified as spinels. In this case, Zn acts as the A cation and Fe as the B cation.

4. **Normal vs. Inverse Spinels**:
In normal spinels, the A cations occupy the tetrahedral sites, and the B cations occupy the octahedral sites in the crystal structure. In inverse spinels, the arrangement is reversed. For `ZnFe₂O₄`, zinc occupies the tetrahedral site, and iron occupies the octahedral sites, which is characteristic of a normal spinel.

5. **Conclusion**:
Based on the analysis, `ZnFe₂O₄` is classified as a normal spinel compound.

### Final Answer:
The compound `ZnFe₂O₄` is a **normal spinel compound**.

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