The co-ordination compound of which one of the following compositions will produce two equivalents of `AgCl` on reaction with aqueous silver nitrate solution

Options

A. `CoCl_(3).3NH_(3)`
B. `CoCl_(3).6NH_(3)`
C. `CoCl_(3).4NH_(3)`
D. `CoCl_(3).5NH_(3)`

Explanation

To determine which coordination compound will produce two equivalents of AgCl when reacted with aqueous silver nitrate (AgNO₃), we need to analyze the coordination compounds and their potential to release chloride ions (Cl⁻) upon reaction.

### Step-by-Step Solution:

1. **Understanding the Reaction**:
- When a coordination compound reacts with AgNO₃, any chloride ions present in the compound will react to form AgCl, a precipitate.
- The formation of two equivalents of AgCl indicates that there are two moles of Cl⁻ ions available in the coordination compound.

2. **Identifying the Coordination Compounds**:
- We need to look at the given options for coordination compounds. Common examples include [CuCl₂], [CoCl₃], [NiCl₂], etc.
- Each compound's formula will indicate how many chloride ions are present.

3. **Counting Chloride Ions**:
- For each coordination compound, count the number of Cl⁻ ions:
- If the compound is [CuCl₂], it has 2 Cl⁻ ions.
- If the compound is [CoCl₃], it has 3 Cl⁻ ions.
- If the compound is [NiCl₂], it has 2 Cl⁻ ions.
- Only those compounds that have exactly 2 Cl⁻ ions will produce 2 equivalents of AgCl.

4. **Selecting the Correct Compound**:
- From the analysis, if we find that [CuCl₂] or [NiCl₂] has 2 chloride ions, they will produce 2 equivalents of AgCl.
- If we find a compound like [CoCl₃], it will produce 3 equivalents of AgCl, which is not what we want.

5. **Conclusion**:
- The coordination compound that produces exactly two equivalents of AgCl upon reaction with AgNO₃ is the one with 2 chloride ions.