`MnO_(4)^(-)` reacts with `Br^(-)` in alkaline pH to give

Options

A. `BrO_(3)^(-),MnO_(2)`
B. `Br_(2),MnO_(4)^(2-)`
C. `Br_(2),MnO_(2)`
D. `BrO^(-),MnO_(4)^(2-)`

Explanation

To solve the problem of what products are formed when \( \text{MnO}_4^{-} \) reacts with \( \text{Br}^{-} \) in alkaline pH, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- \( \text{MnO}_4^{-} \) (permanganate ion)
- \( \text{Br}^{-} \) (bromide ion)
- Alkaline medium (presence of \( \text{OH}^{-} \))

### Step 2: Write the Balanced Reaction
In an alkaline medium, \( \text{MnO}_4^{-} \) acts as an oxidizing agent. The balanced chemical reaction can be written as follows:

\[ \text{MnO}_4^{-} + 2 \text{Br}^{-} + 2 \text{OH}^{-} \rightarrow \text{MnO}_2 + \text{BrO}_3^{-} + \text{H}_2O \]

### Step 3: Identify the Products
From the balanced reaction, we can identify the products:
- \( \text{MnO}_2 \) (manganese dioxide)
- \( \text{BrO}_3^{-} \) (bromate ion)

### Step 4: Conclusion
Thus, when \( \text{MnO}_4^{-} \) reacts with \( \text{Br}^{-} \) in alkaline pH, the products formed are \( \text{BrO}_3^{-} \) and \( \text{MnO}_2 \).

### Final Answer
The products of the reaction are:
- \( \text{BrO}_3^{-} \)
- \( \text{MnO}_2 \)