When phosphine is passed through aqueous solution of copper sulphate, the product produced is

Options

A. `Cu(OH)_(2)`
B. `Cu_(3)P_(2)`
C. `[Cu(PH_(3))_(4)]^(2+)`
D. `[Cu(PH_(3))_(2)]^(2+)`

Explanation

To determine the product formed when phosphine (PH₃) is passed through an aqueous solution of copper sulfate (CuSO₄), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are phosphine (PH₃) and copper sulfate (CuSO₄).

### Step 2: Write the Chemical Equation
The reaction can be represented as:
\[ \text{PH}_3 + \text{CuSO}_4 \rightarrow \text{?} \]

### Step 3: Determine the Products
When phosphine reacts with copper sulfate, it leads to the formation of copper phosphide (Cu₃P₂) and sulfuric acid (H₂SO₄). The balanced chemical equation for this reaction is:
\[ 2 \text{PH}_3 + 3 \text{CuSO}_4 \rightarrow \text{Cu}_3\text{P}_2 + 3 \text{H}_2\text{SO}_4 \]

### Step 4: Identify the Main Product
From the balanced equation, we can see that the main product formed is copper phosphide (Cu₃P₂).

### Step 5: Conclusion
Thus, the product produced when phosphine is passed through an aqueous solution of copper sulfate is:
**Cu₃P₂ (Copper Phosphide)**.