General configuration of outermost and penultimate shell is `(n - 1) s^(2) (n - 1) p^(6) (n - 1)d^(x) ns^(2)`. If `n = 4` and `x = 5` then no. of protons in the nucleus will be

Options

A. gt 25
B. lt 24
C. 25
D. 30

Answer

C

Explanation

Given `n=4x=5`
So `underset(3s^(2))((4-1)s^(2))underset(3p^(6))((4-1))p^(6)underset(3^(5))((4-1))d^(5)underset(4s^(2))(4s^(2))`
`"Total electron"=2+6+5+2=115`
`"Electron in 1 + 2 orbit"=2+8=10`
`"Total electron "=10+15=25`
` "No. of electron = No. of proton, So total proton = 25"`