`NaOH//H^(+)` reacts with

Options

A. `C_(6)H_(5)OCH_(3)`
B. `CH_(3)OH`
C. `CH_(3)-overset(O)overset(||)(C )-CH_(3)`
D. `C_(2)H_(5)OH`

Explanation

To solve the question regarding the reaction of `NaOH/H^(+)` with various compounds, we will analyze each option step by step.

### Step 1: Understand the Reactants
The reactants given are `NaOH` (sodium hydroxide) and `H^+` (proton). Sodium hydroxide is a strong base, and `H^+` is a proton that can act as an acid.

### Step 2: Analyze Each Option
We need to evaluate how each compound reacts with `NaOH/H^(+)`.

1. **Option 1: PHOCH3 (Phenyl Methyl Ether)**
- When `NaOH/H^(+)` is added, the `H^+` will protonate the ether oxygen, but there will be no further reaction because ethers are generally stable under these conditions. Therefore, no product will be formed.

2. **Option 2: Alcohol**
- Similar to option 1, alcohols can undergo protonation by `H^+`, but they do not react further with `NaOH` in this context. Thus, no significant reaction occurs.

3. **Option 3: Acetone (CH3COCH3)**
- Acetone is a ketone and can react with `NaOH/H^(+)`. The `H^+` will protonate the carbonyl oxygen, making it more electrophilic. The `NaOH` can then deprotonate the alpha hydrogen of acetone, leading to the formation of an enolate ion. This enolate can then react further in a nucleophilic addition reaction.

4. **Option 4: Another Alcohol or Compound**
- Similar to options 1 and 2, if this is another alcohol or a stable compound, it will not react significantly with `NaOH/H^(+)`.

### Step 3: Conclusion
After analyzing all options, we conclude that **Option 3 (Acetone)** is the correct answer, as it undergoes a reaction with `NaOH/H^(+)`.

### Final Answer
The compound that reacts with `NaOH/H^(+)` is **Acetone (Option 3)**.

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