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Compound (A) undergoes Cannizzaro reacti...

Compound (A) undergoes Cannizzaro reaction and (B) undergeos positive iodoform test. Therefore

A

A= Acetaldehyde , `B =1`-Pentanal

B

`A= C_(6)H_(5)CH_(2)CHO , B=3`-Pentanone

C

A=Formaldehyde , `B=2`-Pentanone

D

A= Propionaldehyde , `B= 1`-Pentanol

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The correct Answer is:
C

Aldehydes having no `alpha-H` on heating with conc. Alkali undergo disproportionation, known as Cannizzaro reaction. Ketones do not give this reaction. Compounds containing `CH_(3)-CO` group or `CH_(3)-CH-OH` group give positive iodoform test. Among the given options, only option (c ) i.e. `HCHO` and `CH_(3)CH_(2)CH_(2)COCH_(3)` respond to the respective reactions.
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