An organic compound 'A' has the molecular formula `C_(3)H_(6)O`, it undergoes iodoform test. Whet satruated with HCl it gives 'B' of molecular foumula `C_(9)H_(14)O`. A and B, respectively are

Options

A. Propanal and mesitylene
B. Propanone and mesityl oxide
C. Propanone and 2,6-dimethyl -2,5-heptadien-4-one
D. Propanone and mesitylene oxide

Answer

C

Explanation

The compound A with formula `C_(3)H_(6)O` gives iodoform test, it is propanone forms a compound B having carbon atoms three times, the number of carbon atoms in propanone, it is 2,6-dimethyl-2,5-heptadien-4-one.