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|{:(Column I,Column 2,Column 3),((I)"Tol...

`|{:(Column I,Column 2,Column 3),((I)"Toluene",(i)NaOH//Br_(2),(P)"Condensation"),((II)"Acetophenone",(ii)Br_(2)//hv,(Q)"Carboxylation"),((III)"Benzaldehyde",(iii)(CH_(3)CO)_(2)O //CH_(3)COOK,(R)"Substitution"),((IV)"Phenol",(iv)NaOH//CO_(2),(S)"Haloform"):}|`
The only CORRECT combination that gives two different carboxylic acids is

A

(IV) (iii) (Q)

B

(II) (iv) (R )

C

(I) (i) (S)

D

(III) (iii) (P)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the combinations of compounds in Column I with the reactions in Column II and the resulting products in Column III. We are looking for the correct combination that gives two different carboxylic acids. ### Step-by-Step Solution: 1. **Identify the Compounds in Column I**: - (I) Toluene - (II) Acetophenone - (III) Benzaldehyde - (IV) Phenol 2. **Analyze the Reactions in Column II**: - (i) NaOH // Br₂ - (ii) Br₂ // hv - (iii) (CH₃CO)₂O // CH₃COOK - (iv) NaOH // CO₂ 3. **Match the Compounds with the Reactions**: - **Toluene with NaOH // Br₂**: This reaction leads to bromination and does not produce carboxylic acids. - **Acetophenone with Br₂ // hv**: This reaction leads to free radical bromination, which does not produce carboxylic acids. - **Benzaldehyde with (CH₃CO)₂O // CH₃COOK**: This is a reaction that can lead to the formation of carboxylic acids through condensation. - **Phenol with NaOH // CO₂**: This reaction is known as the Kolbe's electrolysis or carboxylation, which can produce two different carboxylic acids. 4. **Identify the Resulting Products**: - **Toluene**: No carboxylic acid produced. - **Acetophenone**: No carboxylic acid produced. - **Benzaldehyde**: Can produce a carboxylic acid but not two different ones. - **Phenol**: Produces two different carboxylic acids (due to the carboxylation reaction). 5. **Conclusion**: The only correct combination that gives two different carboxylic acids is: - (IV) Phenol with (iv) NaOH // CO₂ resulting in (Q) Carboxylation. ### Final Answer: The correct combination is (IV) Phenol with (iv) NaOH // CO₂, which gives two different carboxylic acids. ---

To solve the problem, we need to analyze the combinations of compounds in Column I with the reactions in Column II and the resulting products in Column III. We are looking for the correct combination that gives two different carboxylic acids. ### Step-by-Step Solution: 1. **Identify the Compounds in Column I**: - (I) Toluene - (II) Acetophenone - (III) Benzaldehyde ...
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