`C_(5)H_(13)N` reacts with `HNO_(2)` to give an optically active alcohol The compound is

Options

A. Pentan-1-amine
B. Pentan-2-amine
C. N,N-dimethylpropan-2-amine
D. N-methylbutan-2-amine

Explanation

To solve the problem, we need to identify the compound C5H13N that reacts with HNO2 to yield an optically active alcohol. Here’s a step-by-step solution:

### Step 1: Identify the Structure of C5H13N
C5H13N indicates a compound with five carbon atoms, thirteen hydrogen atoms, and one nitrogen atom. The most likely structure for this compound is an amine, specifically a secondary or tertiary amine, since it has a nitrogen atom that can be converted into an alcohol.

### Step 2: Determine Possible Amines
The amine that fits the formula C5H13N could be:
- Pentan-1-amine (1-aminopentane)
- Pentan-2-amine (2-aminopentane)
- Pentan-3-amine (3-aminopentane)
- Other branched amines

### Step 3: React with HNO2
When an amine reacts with nitrous acid (HNO2), it typically forms an alcohol. The reaction can be summarized as follows:
- The amine (R-NH2) reacts with HNO2 to form an alcohol (R-OH) and nitrogen gas (N2).

### Step 4: Identify Optically Active Alcohol
For the resulting alcohol to be optically active, it must have a chiral center. Among the possible amines, 2-aminopentane (pentan-2-amine) is a suitable candidate because it has a chiral center at the second carbon atom.

### Step 5: Write the Reaction
The reaction of 2-aminopentane with HNO2 can be illustrated as:
\[ \text{C5H13N (2-aminopentane)} + \text{HNO2} \rightarrow \text{C5H12O (2-pentanol)} + \text{N2} + \text{H2O} \]

### Step 6: Conclusion
The compound C5H13N that reacts with HNO2 to give an optically active alcohol is **2-aminopentane** (or pentan-2-amine). The resulting alcohol is **2-pentanol**, which is optically active due to the presence of a chiral center.

### Final Answer
The compound is **2-aminopentane (pentan-2-amine)**.

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