Given the polymers (i) Nylon 66, (ii) Buna-S , (iii) Polythene , arrange these in increasing of their inter-molecular forces (lower to high)

Options

A. `(i) gt (ii) gt (iii) `
B. `(ii) gt(iii)gt(i) `
C. `(ii)lt(iii)lt(i) `
D. `(iii)lt(i)lt(ii) `

Explanation

To arrange the given polymers (i) Nylon 66, (ii) Buna-S, and (iii) Polythene in increasing order of their intermolecular forces, we can analyze the nature of each polymer and the type of intermolecular forces present in them.

### Step-by-Step Solution:

1. **Understanding the Polymers**:
- **Nylon 66**: This is a type of polyamide, which is known for its strong hydrogen bonding between the polymer chains. This results in relatively high intermolecular forces.
- **Buna-S**: This is a synthetic rubber (styrene-butadiene rubber) and is classified as an elastomer. The intermolecular forces in elastomers are generally weaker due to the presence of van der Waals forces.
- **Polythene**: This is a thermoplastic polymer made from the polymerization of ethylene. The intermolecular forces in polythene are primarily weak van der Waals forces, but they are stronger than those in elastomers.

2. **Comparing Intermolecular Forces**:
- **Buna-S** has the weakest intermolecular forces due to its elastomeric nature.
- **Polythene** has stronger intermolecular forces than Buna-S but weaker than Nylon 66.
- **Nylon 66** has the strongest intermolecular forces due to the presence of hydrogen bonds.

3. **Arranging in Increasing Order**:
Based on the analysis above, we can arrange the polymers in increasing order of their intermolecular forces:
- **Buna-S** (weakest)
- **Polythene** (intermediate)
- **Nylon 66** (strongest)

### Final Arrangement:
**Buna-S < Polythene < Nylon 66**