Calculate the molality and mole fraction of 2.5 g of ethanoic acid `(CH_(3)COOH)` in 75 g of benzene.

Explanation

To solve the problem of calculating the molality and mole fraction of 2.5 g of ethanoic acid (CH₃COOH) in 75 g of benzene, we will follow these steps:

### Step 1: Calculate the number of moles of ethanoic acid
To find the number of moles of ethanoic acid, we use the formula:

\[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \]
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