One litre of a solution of N/2 HCl was heated in beaker and it was observed that when the volume of solution got reduce to 600 mL, 3.25 g of HCl was lost. Calculate the normality of the resulting solution.

Explanation

`"1 L of "(N)/(2)" HCl contain HCl "=(1)/(2)xx"36.5 g = 18.25 g , HCl now present "=18.25-3.25g=15g`
`"New volume = 600 ml = 0.600 L, Normality "=(15)/(36.5)" mol"xx(1)/(0.600L)=0.685N.`