A current of dry at was passed through a solution of 2.5 g of a non-volatile substance 'X' in 100 g of w ater and then through water along. The loss of weight of the former was 1.25 g and that of the latter was 0.05 g. Calculate (i) mole fraction of the solute in the solution (ii) molecular weight of the solute.

Explanation

To solve the problem, we need to calculate the mole fraction of the solute in the solution and the molecular weight of the solute. Let's break it down step by step.

### Step 1: Calculate the moles of water (solvent)
We know the mass of water is 100 g. The molar mass of water (H₂O) is approximately 18 g/mol.

\[ \text{Moles of water} = \frac{\text{mass of water}}{\text{molar mass of water}} = \frac{100 \, \text{g}}{18 \, \text{g/mol}} \approx 5.56 \, \text{mol} \]
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