An aqueous solution of glucose boils at `100.01^(@)C`.The molal elevation constant for water is `0.5 kmol^(-1)kg`. The number of molecules of glucose in the solution containing `100g` of water is

Explanation

`Delta T_(b)=K_(b)xx m , 0.01 = 0.5 xx m` which gives m = 0.02.
Thus, 1000 g of water contain glucose = 0.02 mole
`therefore` 100 g of water contain glucose = 0.002 mole `= 0.002 xx 6.02xx10^(23)` molecules `= 1.204xx10^(21)` molecules.