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1.00 g of a non-electrolyte solute disso...

1.00 g of a non-electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.40 K. The freezing point depression constant of benzene is `"5.12 K kg mol"^(-1)`. Find the molar mass of solute.

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To find the molar mass of the non-electrolyte solute, we can use the formula for freezing point depression: \[ \Delta T_f = K_f \cdot m \] where: - \(\Delta T_f\) is the freezing point depression, ...
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1.0 g of non-electrolyte solute dissolved in 50.0 g of benzene lowered the freezing point of benzene by 0.40 K . The freezing point depression constant of benzene is 5.12 kg mol^(-1) . Find the molecular mass of the solute.

(a) State Raoult's law for a solution containing volatile components. How does Raoult' s law become a special case of Henry's law? (b) 1.00 g of a non-electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.40 K. Find the molar mass of the solute. (K_(f)" for benzene "=5.12 kg mol^(-1))

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