A solution containing 2.56 g of sulphur dissolved in 100 g of naphthalene whose melting point is `80^(@)1C` gave a freezing point lowering of `0.680^(@)C`. Calculate the formula of sulphur (`K_(f)` for naphthalene = 6.8 K/m)

Explanation

To solve the problem, we will follow these steps:

### Step 1: Identify the given data
- Mass of sulphur (solute), \( W_2 = 2.56 \, \text{g} \)
- Mass of naphthalene (solvent), \( W_1 = 100 \, \text{g} \)
- Freezing point depression, \( \Delta T_f = 0.680 \, \text{°C} \)
- Freezing point depression constant for naphthalene, \( K_f = 6.8 \, \text{K/m} \)

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