The freezing point of a solution containing `50 cm^(3)` of ethylene glycol in `50 g` of water is found to be `-34^(@)C`. Assuming ideal behaviour, Calculate the density of ethylene glycol `(K_(f)` for water = `1.86 K kg mol^(-1)`).

Explanation

`w_(2)=(M_(2)xxDeltaT_(f)xxw_(1))/(1000xxK_(f))=("62 g mol"^(-1)xx34Kxx50g)/("1000 g kg"^(-1)xx"1.86 K kg mol"^(-1))="56.67 g"`
`d=(w_(2))/(V)=("56.67 g")/("50 cm"^(3))="1.13 g cm"^(-3)`