There is KI and sucrose solution with 0.1 M concentration, if the osmotic pressure of KI and sucorse solution is 0.465 atm and 0.245 atm respectively. Then find the van't Hoff factor of KI and its degree of dissociation.

Explanation

For KI solution `pi` = I CRT
` 0.465 = I 0.1 xx R xx T `
For surcrose solution `pi` = CRT ` :. " " 0.245 = 0.1 xx R xx T `
Dividing (i) by (ii) , we get ` I = (0.465)/(0.245) = 1.898 `
If `alpha` ` {:("If "alpha" is he degree of dissociation, ",KI,hArr,K^(+),+,I^(-)),("Initial","1 mole",,,,),("After disso.",1-alpha,,alpha,,alpha):}`
Total moles after dissociation ` = (1-alpha) + alpha + alpha = 1 + alpha `
` :. i = 1+alpha or alpha = i - 1 = 1.898 -1 = 0.898 = 89.8 ` %