Home
Class 12
CHEMISTRY
Latent heat of fusion of ice is "1436.3 ...

Latent heat of fusion of ice is `"1436.3 cal mol"^(-1)`. Calculate the molal depression constant of water.

Text Solution

AI Generated Solution

To calculate the molal depression constant (Kf) of water using the given latent heat of fusion of ice, we can follow these steps: ### Step 1: Identify the given values - Latent heat of fusion of ice (L) = 1436.3 cal/mol - Molar mass of water (m) = 18 g/mol - Gas constant (R) = 2 cal/(K·mol) - Temperature (T) = 273 K (assumed) ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    PRADEEP|Exercise CURIOSITY QUESTION|4 Videos
  • SOLUTIONS

    PRADEEP|Exercise PROBLEMS FOR PRACTICE|114 Videos
  • SOLUTIONS

    PRADEEP|Exercise IMPORTANT QUESTIONS FOR BOARD EXAMINATION|31 Videos
  • REDOX REACTIONS

    PRADEEP|Exercise Assertion reason type question|16 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    PRADEEP|Exercise Competition (FOCUS) JEE (Main and Advanced)/Medical Entrance SPECIAL (VIII. Assertion-Reason Type Questions)(Type II)|13 Videos

Similar Questions

Explore conceptually related problems

If latent heat of fusion of ice is 80 cals per g at 0^(@), calculate molal depression constant for water.

Molal enthalpy of fusion of water at 273 is 6.0246 kJ mol^(-1) . Calculate mole depression constnt for water.

Latent heat of fusion / melting of ice:

Latent heat of fusion / melting of ice:

Latent heat of fusion of ice is 6kJ mol^(-1) . Calculate the entropy change in the fusion of ice.