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An aqueous fo diabasic acid (molecular m...

An aqueous fo diabasic acid (molecular mass = 118) containing `35.4 g` of acid per litre of the solution has density `1.0077 g mL^(-1)`.
Express the concentration in as many ways as you can?

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The correct Answer is:
0.3 M, 0.6 N, 0.31 m, x (solute)=0.0055, x (solvent) = 0.9945
`"Molarity "=(35.4)/(118)"mol L"^(-1)="0.3M, Noramality "=(35.4)/(118//2)"g eq L"^(-1)=0.6N`
`1000cm^(3) " solution "=1000xx1.0077 g = 1007.7 g`
`"Solvent (water) "=1007.7 - 35.4=972.3 g = 0.9723 kg`
`"Molality "=("35.4/118 mol")/("0.9723 kg")=0.3085 ~=0.31 , x_(2)=(n_(2))/(n_(1)+n_(2))=(35.4//118)/(972.3//18+35.4//118)=0.0055`
`x_(1)=1-x_(2)=0.9945.`
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