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A sugar syrup of weight 214.2g contains ...

A sugar syrup of weight `214.2g` contains `34.2 g` of sugar `(C_(12)H_(22)O_(11))`. Calculate (i) molal concentration and (ii) mole fraction of sugar in the syrup

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The correct Answer is:
(i) 0.556 m (ii) 0.0099
`"Solute "(C_(12)H_(22)O_(11))=34.2g,"Solution = 214.2 g, Solvent = " 214.2-34.2=180 g = 0.180 kg.`
`"Molal conc. "=(34.2//342mol)/(0.180kg)="0.556 mol kg"^(-1)," Mole fraction "=(34.2//342)/(180//18+34.2//342)=0.0099`
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