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Concentrated HNO(3) is 69% by mass of ni...

Concentrated `HNO_(3)` is 69% by mass of nitric acid. Calculate the volume of the solution which contains `23 g` of `HNO_(3)`. (Density of concentrated `HNO_(3)` solution is `1.41 g ml^(-1))`

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The correct Answer is:
`23.6cm^(3)`
`"Conc. Of HNO"_(3)="69 g in 100 g of solution = 69 g in 100/1.41 cm"^(3)," i.e" 70.92cm^(3)`
`therefore" 23 g HNO"_(3)" will be present in solution "=(70.92)/(69)xx23= 23.6cm^(3)`
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