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The density of a "3 M Na(2)S(2)O(3) (sod...

The density of a `"3 M Na_(2)S_(2)O_(3)` (sodium thiosulphate) solution is `"1.25 g cm"^(-3)`. Calculate (i) the percentage by weight of sodium thiosulphate

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To calculate the percentage by weight of sodium thiosulfate (Na₂S₂O₃) in a 3 M solution with a density of 1.25 g/cm³, we can follow these steps: ### Step 1: Understand the Molarity Molarity (M) is defined as the number of moles of solute per liter of solution. A 3 M Na₂S₂O₃ solution means there are 3 moles of sodium thiosulfate in 1 liter of solution. ### Step 2: Calculate the Molar Mass of Na₂S₂O₃ To find the weight of sodium thiosulfate, we first need its molar mass: - Sodium (Na): 22.99 g/mol - Sulfur (S): 32.07 g/mol - Oxygen (O): 16.00 g/mol The molar mass of Na₂S₂O₃ is calculated as: \[ \text{Molar Mass} = (2 \times 22.99) + (2 \times 32.07) + (3 \times 16.00) = 45.98 + 64.14 + 48.00 = 158.12 \text{ g/mol} \] ### Step 3: Calculate the Weight of Sodium Thiosulfate Using the molar mass, we can calculate the weight of sodium thiosulfate in 1 liter of solution: \[ \text{Weight of Na₂S₂O₃} = \text{Number of moles} \times \text{Molar mass} = 3 \text{ moles} \times 158.12 \text{ g/mol} = 474.36 \text{ g} \] ### Step 4: Calculate the Weight of the Solution Next, we need to calculate the total weight of the solution using its density. The density of the solution is given as 1.25 g/cm³. Since 1 liter is equivalent to 1000 cm³: \[ \text{Weight of solution} = \text{Volume} \times \text{Density} = 1000 \text{ cm}^3 \times 1.25 \text{ g/cm}^3 = 1250 \text{ g} \] ### Step 5: Calculate the Percentage by Weight The percentage by weight of sodium thiosulfate in the solution can be calculated using the formula: \[ \text{Percentage by weight} = \left( \frac{\text{Weight of solute}}{\text{Weight of solution}} \right) \times 100 \] Substituting the values we calculated: \[ \text{Percentage by weight} = \left( \frac{474.36 \text{ g}}{1250 \text{ g}} \right) \times 100 \approx 37.89\% \] ### Final Answer The percentage by weight of sodium thiosulfate in the solution is approximately **37.89%**. ---

To calculate the percentage by weight of sodium thiosulfate (Na₂S₂O₃) in a 3 M solution with a density of 1.25 g/cm³, we can follow these steps: ### Step 1: Understand the Molarity Molarity (M) is defined as the number of moles of solute per liter of solution. A 3 M Na₂S₂O₃ solution means there are 3 moles of sodium thiosulfate in 1 liter of solution. ### Step 2: Calculate the Molar Mass of Na₂S₂O₃ To find the weight of sodium thiosulfate, we first need its molar mass: - Sodium (Na): 22.99 g/mol ...
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The density of 3 M sodium of thiosulphate solution (Na_(2)S_(2)O_(3)) is 1.25 g mL^(-1) . Calculate a. The precentage by weight of sodium thiosulphate. b. The mole fraction of sodium thiosulphate. c. The molalities of Na^(o+) and S_(2)O_(3)^(2-) ions.

The density of a 3 M Na_(2) S_(2) O_(3) (sodium thiosulphate) solution is 1.25 g mL^(-1) . Calculate: a. % by weight of Na_(2) S_(2) O_(3) b. Mole fraction of Na_(2) S_(2) O_(3) c. Molalities of Na^(o+) and S_(2) O_(3)^(2-) ions.

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The density of 3 M solution of sodium thiosulphate (Na_(2)S_(2)O_(3)) is 1.25 g/mL. Calculate amount of sodium thiosulphate

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