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20 g of solute was added to 100 g of wat...

20 g of solute was added to 100 g of water at `25^(@)C`. The vapour pressure of water and that of solution were 23.76 mm Hg and 22.41 mm Hg respectively at the temperature. Calculate the relative molecular mass of the solute.

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To solve the problem step by step, we will use the concept of relative lowering of vapor pressure. Here’s how we can calculate the relative molecular mass of the solute. ### Step 1: Write down the given data - Mass of solute (B) = 20 g - Mass of solvent (water, A) = 100 g - Vapor pressure of pure water (P₀) = 23.76 mm Hg - Vapor pressure of the solution (P) = 22.41 mm Hg ...
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Twenty grams of a solute are added to 100g of water at 25^(@)C . The vapour pressure of pure water is 23.76 mmHg , the vapour pressure of the solution is 22.41 Torr. (a) Calculate the molar mass of the solute. (b) What mass of this solute is required in 100g of water of reduce the vapour pressure ot one-half the value for pure water?

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