A solution containing 10.2 g of glycrine per litre is found to be isotonic with 2% solution of glucose `("molar mass"=180 g mol^(-1))`. Calculate the molar mass of glycrine.

Answer

91.9 u

Explanation

`"Molar conc. of glycerine "=10.2//M" (M = mol. mass)"`
`"Molar conc. of glucose "=(2)/(180)xx(1)/(100)xx1000="0.111 mol L"^(-1)" "therefore" "(10.2)/(M_(2))=0.111" or "M_(2)=91.9"g mol"^(-1)`.