100 mg of a protein was disoved in just ...

100 mg of a protein was disoved in just enough water to make 10 mL of the solution. If the solution has an osmotic pressure of 13.3 mm Hg at `25^(@)C`, what is the mass of prtein `(R=0.0821 L atm mol^(-1)K^(-1))`

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The correct Answer is:

`"13980.4 g mol"^(-1)`

`M_(2)=(wRT)/(piV)=((8.95xx10^(-3)g)(0.0821"L atm K"^(-1)"mol"^(-1))(298K))/(("0.335/760 atm")(35xx10^(-3)L))="14193.3 g mol"^(-1)`

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