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When 1.80 g of non-volatile compound is ...

When 1.80 g of non-volatile compound is dissolved in 25.0 g of acetone, the solution boils at `56.86^(@)C` while pure acetone boils at `56.38^(@)C` under the same atmospheric pressure. Calculate the molar mass of compound. The molal elevation constant for acetone is `1.72^(@)`.

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To calculate the molar mass of the non-volatile compound, we can follow these steps: ### Step 1: Determine the boiling point elevation The boiling point elevation (ΔT_b) can be calculated using the formula: \[ \Delta T_b = T_b(\text{solution}) - T_b(\text{pure solvent}) \] Where: ...
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