A solution of glycerol `(C-(3)H_(8)O_(3)` , molar mass = 92 g `mol^(-1)` iin water was prepared by dissolving some glycero 500 g of water. This solution has a boiling point of `100.42^(@)C`. What mass of glycerol was dissolved to make this solution ? `K_(b)` for water=` 0.512 k kg mol^(-1).`

Answer

`37.7g`

Explanation

`DeltaT_(b)=(100K_(b)w_(2))/(w_(1)M_(2))" or "w_(2)=(w_(1)M_(2)DeltaT_(b))/(1000K_(b))=(500xx92xx0.42)/(1000xx0.512)=37.7g`