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The addition of 0.643 g of a compound to...

The addition of `0.643 g` of a compound to `50 mL` of benzene (density 0.879 g `mL^(-1)`) lowers the freezing point from `5.51` to `5.03^(@)C`. If `K_(f)` for benzene is `5.12`, calculate the molecular weight of the compound.

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The correct Answer is:
156 u
`w_(2)=0.643g, w_(1)=50xx0.879 g = 43.95g.`
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Addition of 0.643g of a compound to 50mL of benzene (density: 0.879g mL^(-1)) lower the freezing point from 5.51^(@)C to 5.03^(@)C . If K_(f) for benzene is 5.12 K kg mol^(-1) , calculate the molar mass of the compound.

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