Datermine the osmotic pressure of a solution prepared by dissolving `2.5xx10^(-2)g" of " K_2SO_4` in 2L of water at `25^@C`, assuming that it is completely dissociated.
(R = 0.0821 atm `K^(-1)` mol^(-1),Molar mass of `K_2SO_4`=174 g mol^(-1)`).

Answer

`5.27xx10^(-3)atm`

Explanation

`K_(2)SO_(4)rarr2K^(+)+SO_(4)^(2-) thereforei=3," "C=(2.5xx10^(-2))/(174)xx(1)/(2)=7.18xx10^(-5)"mol L"^(-1)`
`pi="i CRT, "pi=(3)(7.18xx10^(-5)" mol L"^(-1))("0.0821 L atm K"^(-1)"mol"^(-1))(298K)=5.27xx10^(-3)"atm"`