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Phenol associates in benzene to a certai...

Phenol associates in benzene to a certain extent to form a dimer. A solution containing `20xx10^(-1)` kg phenol in 1 kg of benzene has its freezing pint depressed by 0.69 K. Calculate the fraction of phenol that has dimerised. `"K"_("f")" for benzene"=5.12" kg mol"^(-1)"k"`.

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The correct Answer is:
0.734

`M_(2)"(observed)"=(1000K_(f)w_(2))/(w_(1)DeltaT_(f))=("1000 g kg"^(-1)xx"5.12 K kg mol"^(-1)xx2.0xx10^(-2)kg)/(1.0kg xx0.69K)="148.4 g mol"^(-1)`
`M_(2)"(calculated) for "C_(6)H_(5)OH="94 g mol"^(-1)" "therefore" "i=(M_(2)"(calculated)")/(M_(2)"(observed)")=(94)/(148.4)=0.633`
`{:(,2C_(6)H_(5)OHhArr(C_(6)H_(5)OH)_(2)),("Initial"," 1mol"),("After asso."," "1-alpha" "alpha//2" Total "=1-alpha//2):}`
`i=(1-alpha//2)/(1)" or "alpha=2(1-i)=2(1-0.633)=0.734.`
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Phenol associates in benzene to certain extent to form a dimer. A solution containing 20 xx 10^(-3) kg of phenol in 1.0 kg of benzene hs its freezing point depressed by 0.69 K . Calculate the fraction of phenol that has dimerized. ( K_(f) for benzene is 5.12 K kg mol^(-1) ).

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phenol associates in benzene to a certain extent in dimerisation reaction. A solution containing 0.02 kg of phenol in 1.0 kg of benzene has its freezing point depressed 0.69 k. [ K_(f)(_(6)H_(6)) =5.12 k "mol"^(-1) ]

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