On a certain hill station, pure water is found to boil at `95^(@)C`. How many grams of NaCl must be added to 2 kg of water so that it boils at `100^(@)C`?

Answer

562.42 g

Explanation

`DeltaT_(b)=100-95=5^(@),DeltaT_(b)=iK_(b)m" or "m=(DeltaT_(b))/(iK_(b))=(5)/(2xx0.52)=4.807`
`"1000 g should contain NaCl = 4.807 moles "=4.807xx58.5g`
`therefore" 2000 g should contain NaCl "=2xx4.807xx58.7=562.42g.`